>.... 80MM calipers and
>resultant pads produce more force against the rotor with the same PSI from
>the master cylinder
Using larger calipers or slave cylinders and the same master cylinder:
(More Caliper or Cylinder Force) ~ (More Peddle Travel) * (Same Peddle=
=20
Pressure)
How Much More:
(New Percentage) ( (New Dia / 2 ) * ( New Dia / 2 ) * 314 ) / ( (Old Dia=
=20
/ 2) * (Old Dia / 2) * 3.14 )
For example, when I replaced my 15/16" (.938") rear cylinders with 1 1/8"=20
(1.13") cylinders I get:
( (1.13 / 2 ) * ( 1.13 / 2 ) * 314 ) / ( ( .938 / 2) * ( .938 / 2) *=20
3.14 )
( .565 * .565 * 314) / ( .469 * .469 * 3.14 )
100 / .691 144%
So the force on my rear shoes (given the same peddle pressure) is now 144%=
=20
of what it was before the upgrade and the peddle travel (given the same=20
peddle pressure) is roughly 144% of what it was before the upgrade.
But this assumes that all of the peddle travel is a result of the movement=
=20
of the brake shoes, the compression of the brake shoes and the expansion of=
=20
the drum. In reality much of the peddle travel is a result of compression=20
of the brake fluid (Almost stays the same because the peddle pressure is=20
the same, although there is a bit more fluid to compress) and expansion of=
=20
the brake lines (stays the same). In reality the peddle travel after the=20
upgrade is not 144% but something less. This is consistent with what I=20
experienced after I did the upgrade. In fact, I cant really say that=20
increased peddle travel is all that noticeable. I suspect that much of the=
=20
peddle travel (before and after) is related to compression of the brake=20
fluid and expansion of the brake lines.
Notes:
* is multiply
/ is divide
( ) do the stuff in the parenthesis first
~ means roughly equal to
Works with metric or English.
Dave
Ann Arbor, MI.
73 Sequoia (26'/455/HEI/TBI/160=B0/3.42)
>resultant pads produce more force against the rotor with the same PSI from
>the master cylinder
Using larger calipers or slave cylinders and the same master cylinder:
(More Caliper or Cylinder Force) ~ (More Peddle Travel) * (Same Peddle=
=20
Pressure)
How Much More:
(New Percentage) ( (New Dia / 2 ) * ( New Dia / 2 ) * 314 ) / ( (Old Dia=
=20
/ 2) * (Old Dia / 2) * 3.14 )
For example, when I replaced my 15/16" (.938") rear cylinders with 1 1/8"=20
(1.13") cylinders I get:
( (1.13 / 2 ) * ( 1.13 / 2 ) * 314 ) / ( ( .938 / 2) * ( .938 / 2) *=20
3.14 )
( .565 * .565 * 314) / ( .469 * .469 * 3.14 )
100 / .691 144%
So the force on my rear shoes (given the same peddle pressure) is now 144%=
=20
of what it was before the upgrade and the peddle travel (given the same=20
peddle pressure) is roughly 144% of what it was before the upgrade.
But this assumes that all of the peddle travel is a result of the movement=
=20
of the brake shoes, the compression of the brake shoes and the expansion of=
=20
the drum. In reality much of the peddle travel is a result of compression=20
of the brake fluid (Almost stays the same because the peddle pressure is=20
the same, although there is a bit more fluid to compress) and expansion of=
=20
the brake lines (stays the same). In reality the peddle travel after the=20
upgrade is not 144% but something less. This is consistent with what I=20
experienced after I did the upgrade. In fact, I cant really say that=20
increased peddle travel is all that noticeable. I suspect that much of the=
=20
peddle travel (before and after) is related to compression of the brake=20
fluid and expansion of the brake lines.
Notes:
* is multiply
/ is divide
( ) do the stuff in the parenthesis first
~ means roughly equal to
Works with metric or English.
Dave
Ann Arbor, MI.
73 Sequoia (26'/455/HEI/TBI/160=B0/3.42)